• hddsx@lemmy.ca
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    5 months ago

    No. F=GMm/d2. The mass of the earth doesn’t change so g=GM/d2 will not change

    • Tar_Alcaran@sh.itjust.works
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      5 months ago

      Ah but the earth doesn’t just attract the ball or feather. The bowling ball attracts the earth as well, and since it has more mass, it will pull the earth towards it faster than the feather.

      But if you drop them at the same time, that’s moot.

      • hddsx@lemmy.ca
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        5 months ago

        In other words, the feather and ball are both attracted to the earth at the same rate but because the ball has a higher mass, the earth is very slightly more attracted to the ball

    • JohnDClay@sh.itjust.works
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      5 months ago

      So why does the bowling ball fall faster in a vacuum? Does it appear faster locally because the heavier object makes local time slower than the lighter object compared to a distant observer? I’m trying to understand what the meme is getting at.

      • Drewfro66@lemmygrad.ml
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        5 months ago

        The bowling ball also pulls the earth towards itself. This amount is imperceptibly small but still there

      • dev_null@lemmy.ml
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        5 months ago

        Because it, ever so slightly, pulls Earth towards it with it’s own, miniscule gravity.

        • JohnDClay@sh.itjust.works
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          5 months ago

          But that doesn’t make the bowling ball fall faster to a distant observer, just the earth fall twords the ball. To an observer on earth it would appear to fall faster though.